1-y+4(y-2)=5

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Solution for 1-y+4(y-2)=5 equation: 



1-y+4(y-2)=5

We move all terms to the left:

1-y+4(y-2)-(5)=0

We add all the numbers together, and all the variables

-1y+4(y-2)-4=0

We multiply parentheses

-1y+4y-8-4=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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