1.04=(0.9)x+(1.1)(1-x)

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Solution for 1.04=(0.9)x+(1.1)(1-x) equation:



1.04=(0.9)x+(1.1)(1-x)
We move all terms to the left:
1.04-((0.9)x+(1.1)(1-x))=0
We add all the numbers together, and all the variables
-((0.9)x+(1.1)(-1x+1))+1.04=0
We multiply parentheses ..
-((0.9)x+(-1.1x+1.1))+1.04=0
We calculate terms in parentheses: -((0.9)x+(-1.1x+1.1)), so:
(0.9)x+(-1.1x+1.1)
We multiply parentheses
0.9x+(-1.1x+1.1)
We get rid of parentheses
0.9x-1.1x+1.1
We add all the numbers together, and all the variables
-0.2x+1.1
Back to the equation:
-(-0.2x+1.1)
We get rid of parentheses
0.2x-1.1+1.04=0
We add all the numbers together, and all the variables
0.2x-0.06=0
We move all terms containing x to the left, all other terms to the right
0.2x=0.06
x=0.06/0.2
x=0.06/0.2

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