1.06(550+x)=2(212+2x*1.06)

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Solution for 1.06(550+x)=2(212+2x*1.06) equation: 



1.06(550+x)=2(212+2x*1.06)

We move all terms to the left:

1.06(550+x)-(2(212+2x*1.06))=0

We add all the numbers together, and all the variables

1.06(x+550)-(2(2x*1.06+212))=0

We multiply parentheses

1.06x-(2(2x*1.06+212))+583=0



We calculate terms in parentheses: -(2(2x*1.06+212)), so:

2(2x*1.06+212)

We multiply parentheses

4.24x+424

Back to the equation:

-(4.24x+424)



We get rid of parentheses

1.06x-4.24x-424+583=0

We add all the numbers together, and all the variables

-3.18x+159=0

We move all terms containing x to the left, all other terms to the right

-3.18x=-159

x=-159/-3.18

x=+50

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