1.08(2t+2.50)+3=13.801.08(2t+2.50)+3=13.80

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Solution for 1.08(2t+2.50)+3=13.801.08(2t+2.50)+3=13.80 equation:



1.08(2t+2.50)+3=13.801.08(2t+2.50)+3=13.80
We move all terms to the left:
1.08(2t+2.50)+3-(13.801.08(2t+2.50)+3)=0
We add all the numbers together, and all the variables
1.08(2t+2.5)-(13.801.08(2t+2.5)+3)+3=0
We multiply parentheses
2.16t-(13.801.08(2t+2.5)+3)+2.7+3=0
We calculate terms in parentheses: -(13.801.08(2t+2.5)+3), so:
13.801.08(2t+2.5)+3
We multiply parentheses
2.20816t+2.7602+3
We add all the numbers together, and all the variables
2.20816t+5.7602
Back to the equation:
-(2.20816t+5.7602)
We add all the numbers together, and all the variables
2.16t-(2.20816t+5.7602)+5.7=0
We get rid of parentheses
2.16t-2.20816t-5.7602+5.7=0
We add all the numbers together, and all the variables
-0.04816t-0.0602=0
We move all terms containing t to the left, all other terms to the right
-0.04816t=0.0602
t=0.0602/-0.04816
t=-1+0.01204/0.04816

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