1.2(15z-10)+6=3(2z+11)

Solution for 1.2(15z-10)+6=3(2z+11) equation:

1.2(15z-10)+6=3(2z+11)

We move all terms to the left:

1.2(15z-10)+6-(3(2z+11))=0

We multiply parentheses

18z-(3(2z+11))-12+6=0


We calculate terms in parentheses: -(3(2z+11)), so:

3(2z+11)

We multiply parentheses

6z+33

Back to the equation:

-(6z+33)


We add all the numbers together, and all the variables

18z-(6z+33)-6=0

We get rid of parentheses

18z-6z-33-6=0

We add all the numbers together, and all the variables

12z-39=0

We move all terms containing z to the left, all other terms to the right

12z=39

z=39/12

z=3+1/4