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1.25x^2=5.05
We move all terms to the left:
1.25x^2-(5.05)=0
We add all the numbers together, and all the variables
1.25x^2-5.05=0
a = 1.25; b = 0; c = -5.05;
Δ = b2-4ac
Δ = 02-4·1.25·(-5.05)
Δ = 25.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.25}}{2*1.25}=\frac{0-\sqrt{25.25}}{2.5} =-\frac{\sqrt{}}{2.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.25}}{2*1.25}=\frac{0+\sqrt{25.25}}{2.5} =\frac{\sqrt{}}{2.5} $
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