1.2=(4.9t-0.5)t

Solution for 1.2=(4.9t-0.5)t equation:

1.2=(4.9t-0.5)t

We move all terms to the left:

1.2-((4.9t-0.5)t)=0


We calculate terms in parentheses: -((4.9t-0.5)t), so:

(4.9t-0.5)t

We multiply parentheses

4t^2-0.5t

Back to the equation:

-(4t^2-0.5t)


We get rid of parentheses

-4t^2+0.5t+1.2=0

a = -4; b = 0.5; c = +1.2;
Δ = b2-4ac
Δ = 0.52-4·(-4)·1.2
Δ = 19.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{19.45}}{2*-4}=\frac{-0.5-\sqrt{19.45}}{-8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{19.45}}{2*-4}=\frac{-0.5+\sqrt{19.45}}{-8}
$