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1.2=x(1-x)
We move all terms to the left:
1.2-(x(1-x))=0
We add all the numbers together, and all the variables
-(x(-1x+1))+1.2=0
We calculate terms in parentheses: -(x(-1x+1)), so:We get rid of parentheses
x(-1x+1)
We multiply parentheses
-1x^2+x
Back to the equation:
-(-1x^2+x)
1x^2-x+1.2=0
We add all the numbers together, and all the variables
x^2-1x+1.2=0
a = 1; b = -1; c = +1.2;
Δ = b2-4ac
Δ = -12-4·1·1.2
Δ = -3.8
Delta is less than zero, so there is no solution for the equation
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