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1.2x-2.7=3(1/5x+1)
We move all terms to the left:
1.2x-2.7-(3(1/5x+1))=0
Domain of the equation: 5x+1))!=0We multiply all the terms by the denominator
x∈R
(1.2x)*5x-(2.7)*5x+1))-(3(1+1))=0
We add all the numbers together, and all the variables
(+1.2x)*5x-(2.7)*5x+1))-(32)=0
We add all the numbers together, and all the variables
(+1.2x)*5x-(2.7)*5x=0
We multiply parentheses
5x^2-13.5x=0
a = 5; b = -13.5; c = 0;
Δ = b2-4ac
Δ = -13.52-4·5·0
Δ = 182.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13.5)-\sqrt{182.25}}{2*5}=\frac{13.5-\sqrt{182.25}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13.5)+\sqrt{182.25}}{2*5}=\frac{13.5+\sqrt{182.25}}{10} $
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