1.30x-(x-2.30)(3.10x-5.40)-2.88=4.60-(3.10-1.20)(x-5.30)-4.30x

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Solution for 1.30x-(x-2.30)(3.10x-5.40)-2.88=4.60-(3.10-1.20)(x-5.30)-4.30x equation:



1.30x-(x-2.30)(3.10x-5.40)-2.88=4.60-(3.10-1.20)(x-5.30)-4.30x
We move all terms to the left:
1.30x-(x-2.30)(3.10x-5.40)-2.88-(4.60-(3.10-1.20)(x-5.30)-4.30x)=0
We add all the numbers together, and all the variables
1.30x-(x-2.3)(3.10x-5.4)-(4.60-(1.9)(x-5.3)-4.30x)-2.88=0
We multiply parentheses ..
-(+3x^2-5.4x-6.9x+12.42)+1.30x-(4.60-(1.9)(x-5.3)-4.30x)-2.88=0
We calculate terms in parentheses: -(4.60-(1.9)(x-5.3)-4.30x), so:
4.60-(1.9)(x-5.3)-4.30x
determiningTheFunctionDomain -(1.9)(x-5.3)-4.30x+4.60
We add all the numbers together, and all the variables
-4.3x-(1.9)(x-5.3)+4.6
We multiply parentheses ..
-4.3x-(+1.9x-10.07)+4.6
We add all the numbers together, and all the variables
-4.3x-(1.9x-10.07)+4.6
We get rid of parentheses
-4.3x-1.9x+10.07+4.6
We add all the numbers together, and all the variables
-6.2x+14.67
Back to the equation:
-(-6.2x+14.67)
We get rid of parentheses
-3x^2+5.4x+6.9x+1.30x+6.2x-12.42-14.67-2.88=0
We add all the numbers together, and all the variables
-3x^2+19.8x-29.97=0
a = -3; b = 19.8; c = -29.97;
Δ = b2-4ac
Δ = 19.82-4·(-3)·(-29.97)
Δ = 32.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19.8)-\sqrt{32.4}}{2*-3}=\frac{-19.8-\sqrt{32.4}}{-6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19.8)+\sqrt{32.4}}{2*-3}=\frac{-19.8+\sqrt{32.4}}{-6} $

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