1.43=48t2

Solution for 1.43=48t2 equation:

1.43=48t^2

We move all terms to the left:

1.43-(48t^2)=0

a = -48; b = 0; c = +1.43;
Δ = b2-4ac
Δ = 02-4·(-48)·1.43
Δ = 274.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{274.56}}{2*-48}=\frac{0-\sqrt{274.56}}{-96}
=-\frac{\sqrt{}}{-96}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{274.56}}{2*-48}=\frac{0+\sqrt{274.56}}{-96}
=\frac{\sqrt{}}{-96}
$