1.44=q2

Solution for 1.44=q2 equation:

1.44=q2

We move all terms to the left:

1.44-(q2)=0

We add all the numbers together, and all the variables

-1q^2+1.44=0

a = -1; b = 0; c = +1.44;
Δ = b2-4ac
Δ = 02-4·(-1)·1.44
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5.76}}{2*-1}=\frac{0-\sqrt{5.76}}{-2}
=-\frac{\sqrt{}}{-2}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5.76}}{2*-1}=\frac{0+\sqrt{5.76}}{-2}
=\frac{\sqrt{}}{-2}
$