1.4t(t-3.1)=5.8

Solution for 1.4t(t-3.1)=5.8 equation:

1.4t(t-3.1)=5.8

We move all terms to the left:

1.4t(t-3.1)-(5.8)=0

We add all the numbers together, and all the variables

1.4t(t-3.1)-5.8=0

We multiply parentheses

t^2-3.1t-5.8=0

a = 1; b = -3.1; c = -5.8;
Δ = b2-4ac
Δ = -3.12-4·1·(-5.8)
Δ = 32.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.1)-\sqrt{32.81}}{2*1}=\frac{3.1-\sqrt{32.81}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.1)+\sqrt{32.81}}{2*1}=\frac{3.1+\sqrt{32.81}}{2}
$