1.4x+(5x=5.25)x2=4.25x+(3x-7.5)x2

Solution for 1.4x+(5x=5.25)x2=4.25x+(3x-7.5)x2 equation:

1.4x+(5x=5.25)x2=4.25x+(3x-7.5)x2

We move all terms to the left:

1.4x+(5x-(5.25)x2)=0


We calculate terms in parentheses: +(5x-(5.25)x2), so:

5x-(5.25)x2

We multiply parentheses

-5.25x^2+5x

Back to the equation:

+(-5.25x^2+5x)


We get rid of parentheses

-5.25x^2+5x+1.4x=0

We add all the numbers together, and all the variables

-5.25x^2+6.4x=0

a = -5.25; b = 6.4; c = 0;
Δ = b2-4ac
Δ = 6.42-4·(-5.25)·0
Δ = 40.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.4)-\sqrt{40.96}}{2*-5.25}=\frac{-6.4-\sqrt{40.96}}{-10.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.4)+\sqrt{40.96}}{2*-5.25}=\frac{-6.4+\sqrt{40.96}}{-10.5}
$