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1.52y=3.17y(y-8.57)
We move all terms to the left:
1.52y-(3.17y(y-8.57))=0
We calculate terms in parentheses: -(3.17y(y-8.57)), so:We get rid of parentheses
3.17y(y-8.57)
We multiply parentheses
3y^2-25.71y
Back to the equation:
-(3y^2-25.71y)
-3y^2+1.52y+25.71y=0
We add all the numbers together, and all the variables
-3y^2+27.23y=0
a = -3; b = 27.23; c = 0;
Δ = b2-4ac
Δ = 27.232-4·(-3)·0
Δ = 741.4729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27.23)-\sqrt{741.4729}}{2*-3}=\frac{-27.23-\sqrt{741.4729}}{-6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27.23)+\sqrt{741.4729}}{2*-3}=\frac{-27.23+\sqrt{741.4729}}{-6} $
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