1.56(0.25-x)(0.25-x)=0

Solution for 1.56(0.25-x)(0.25-x)=0 equation:

1.56(0.25-x)(0.25-x)=0

We add all the numbers together, and all the variables

1.56(-1x+0.25)(-1x+0.25)=0

We multiply parentheses ..

1.56(+x^2-0.25x-0.25x+0.0625)=0

We multiply parentheses

1.56x^2+0x+0x+0.0975=0

We add all the numbers together, and all the variables

1.56x^2+2x+0.0975=0

a = 1.56; b = 2; c = +0.0975;
Δ = b2-4ac
Δ = 22-4·1.56·0.0975
Δ = 3.3916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{3.3916}}{2*1.56}=\frac{-2-\sqrt{3.3916}}{3.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{3.3916}}{2*1.56}=\frac{-2+\sqrt{3.3916}}{3.12}
$