1.5m(2)=15.48

Solution for 1.5m(2)=15.48 equation:

1.5m(2)=15.48

We move all terms to the left:

1.5m(2)-(15.48)=0

We add all the numbers together, and all the variables

1.5m^2-15.48=0

a = 1.5; b = 0; c = -15.48;
Δ = b2-4ac
Δ = 02-4·1.5·(-15.48)
Δ = 92.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{92.88}}{2*1.5}=\frac{0-\sqrt{92.88}}{3}
=-\frac{\sqrt{}}{3}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{92.88}}{2*1.5}=\frac{0+\sqrt{92.88}}{3}
=\frac{\sqrt{}}{3}
$