1.5t2-50t-50=0

Solution for 1.5t2-50t-50=0 equation:

1.5t^2-50t-50=0

a = 1.5; b = -50; c = -50;
Δ = b2-4ac
Δ = -502-4·1.5·(-50)
Δ = 2800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2800}=\sqrt{400*7}=\sqrt{400}*\sqrt{7}=20\sqrt{7}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-20\sqrt{7}}{2*1.5}=\frac{50-20\sqrt{7}}{3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+20\sqrt{7}}{2*1.5}=\frac{50+20\sqrt{7}}{3}
$