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1.5x(x+3)=0.5(x-1)
We move all terms to the left:
1.5x(x+3)-(0.5(x-1))=0
We multiply parentheses
x^2+3x-(0.5(x-1))=0
We calculate terms in parentheses: -(0.5(x-1)), so:We get rid of parentheses
0.5(x-1)
We multiply parentheses
0.5x-0.5
Back to the equation:
-(0.5x-0.5)
x^2+3x-0.5x+0.5=0
We add all the numbers together, and all the variables
x^2+2.5x+0.5=0
a = 1; b = 2.5; c = +0.5;
Δ = b2-4ac
Δ = 2.52-4·1·0.5
Δ = 4.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{4.25}}{2*1}=\frac{-2.5-\sqrt{4.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{4.25}}{2*1}=\frac{-2.5+\sqrt{4.25}}{2} $
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