1.60=-x2+40x+29

Solution for 1.60=-x2+40x+29 equation:

1.60=-x2+40x+29

We move all terms to the left:

1.60-(-x2+40x+29)=0

We add all the numbers together, and all the variables

-(-1x^2+40x+29)+1.60=0

We add all the numbers together, and all the variables

-(-1x^2+40x+29)+1.6=0

We get rid of parentheses

1x^2-40x-29+1.6=0

We add all the numbers together, and all the variables

x^2-40x-27.4=0

a = 1; b = -40; c = -27.4;
Δ = b2-4ac
Δ = -402-4·1·(-27.4)
Δ = 1709.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-\sqrt{1709.6}}{2*1}=\frac{40-\sqrt{1709.6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+\sqrt{1709.6}}{2*1}=\frac{40+\sqrt{1709.6}}{2}
$