1.68=(2+3y)y

Solution for 1.68=(2+3y)y equation:

1.68=(2+3y)y

We move all terms to the left:

1.68-((2+3y)y)=0

We add all the numbers together, and all the variables

-((3y+2)y)+1.68=0


We calculate terms in parentheses: -((3y+2)y), so:

(3y+2)y

We multiply parentheses

3y^2+2y

Back to the equation:

-(3y^2+2y)


We get rid of parentheses

-3y^2-2y+1.68=0

a = -3; b = -2; c = +1.68;
Δ = b2-4ac
Δ = -22-4·(-3)·1.68
Δ = 24.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{24.16}}{2*-3}=\frac{2-\sqrt{24.16}}{-6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{24.16}}{2*-3}=\frac{2+\sqrt{24.16}}{-6}
$