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1.6x^2+4x+1.5=0
a = 1.6; b = 4; c = +1.5;
Δ = b2-4ac
Δ = 42-4·1.6·1.5
Δ = 6.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{6.4}}{2*1.6}=\frac{-4-\sqrt{6.4}}{3.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{6.4}}{2*1.6}=\frac{-4+\sqrt{6.4}}{3.2} $
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