1/(12d)-4/(3d)=15

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Solution for 1/(12d)-4/(3d)=15 equation: 


D( d )

3*d = 0

12*d = 0

3*d = 0

3*d = 0

3*d = 0 // : 3

d = 0

12*d = 0

12*d = 0

12*d = 0 // : 12

d = 0

d in (-oo:0) U (0:+oo)

1/(12*d)-(4/(3*d)) = 15 // - 15

1/(12*d)-(4/(3*d))-15 = 0

1/(12*d)+(-4/3)*d^-1-15 = 0

-5/4*d^-1 = 15 // : -5/4

d^-1 = -12

-1 < 0

1/(d^1) = -12 // * d^1

1 = -12*d^1 // : -12

-1/12 = d^1

d = -1/12

d = -1/12

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