1/(2/y)+y=3

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Solution for 1/(2/y)+y=3 equation: 


D( y )

y = 0

2/y = 0

y = 0

y = 0

2/y = 0

2/y = 0

2*y^-1 = 0 // : 2

y^-1 = 0

y naleu017Cy do O

y in (-oo:0) U (0:+oo)

1/(2/y)+y = 3 // - 3

1/(2/y)+y-3 = 0

3/2*y-3 = 0 // + 3

3/2*y = 3 // : 3/2

y = 3/3/2

y = 2

y = 2

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