1/(2x)=1/10+4/6+x

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Solution for 1/(2x)=1/10+4/6+x equation: 


D( x )

2*x = 0

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:0) U (0:+oo)

1/(2*x) = x+1/10+4/6 // - x+1/10+4/6

1/(2*x)-x-(1/10)-(4/6) = 0

1/(2*x)-x-1/10-2/3 = 0

1/2*x^-1-1*x^1-23/30*x^0 = 0

(1/2*x^0-1*x^2-23/30*x^1)/(x^1) = 0 // * x^2

x^1*(1/2*x^0-1*x^2-23/30*x^1) = 0

x^1

(-23/30)*x-x^2+1/2 = 0

(-23/30)*x-x^2+1/2 = 0

DELTA = (-23/30)^2-(-1*4*(1/2))

DELTA = 2329/900

DELTA > 0

x = ((2329/900)^(1/2)-(-23/30))/(-1*2) or x = (-(-23/30)-(2329/900)^(1/2))/(-1*2)

x = ((2329/900)^(1/2)+23/30)/(-2) or x = (23/30-(2329/900)^(1/2))/(-2)

x in { ((2329/900)^(1/2)+23/30)/(-2), (23/30-(2329/900)^(1/2))/(-2)} 

x in { ((2329/900)^(1/2)+23/30)/(-2), (23/30-(2329/900)^(1/2))/(-2) }

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