1/(2x+6)-3/2x=1/(x+3)

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Solution for 1/(2x+6)-3/2x=1/(x+3) equation:



1/(2x+6)-3/2x=1/(x+3)
We move all terms to the left:
1/(2x+6)-3/2x-(1/(x+3))=0
Domain of the equation: (2x+6)!=0
We move all terms containing x to the left, all other terms to the right
2x!=-6
x!=-6/2
x!=-3
x∈R
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: (x+3))!=0
x∈R
We calculate fractions
(2x^2*()/((2x+6)*2x*(x+3)))+(-3*(2x+6)*(x+3)))/((2x+6)*2x*(x+3)))+(-(1*(2x+6)*2x)/((2x+6)*2x*(x+3)))=0
We calculate terms in parentheses: +(2x^2*()/((2x+6)*2x*(x+3))), so:
2x^2*()/((2x+6)*2x*(x+3))
We multiply all the terms by the denominator
2x^2*()
Back to the equation:
+(2x^2*())
We calculate terms in parentheses: +(-3*(2x+6)*(x+3)))/((2x+6)*2x*(x+3)))+(-(1*(2x+6)*2x)/((2x+6)*2x*(x+3))), so:
-3*(2x+6)*(x+3)))/((2x+6)*2x*(x+3)))+(-(1*(2x+6)*2x)/((2x+6)*2x*(x+3))
We add all the numbers together, and all the variables
-3*(2x+6)*(x+3)))/((2x+6)*2x*(x+3)))+(-(1*(2x+6)*2x)/((2x+6)*2x*(x
We multiply all the terms by the denominator
-3*(2x+6)*(x+3)))+6*2x*x*((2x+3))+(-(1*2x*((2x+6)*2x)+6*2x*x*((2x
Wy multiply elements
12x^3*x-3*(2x+6)*(x+3)))+6*2x*x*((2x+3))+(-(1*2x*((2x+6)*2x)
We do not support expression: x^3

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