If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/(2x+6)-3/2x=1/(x+3)
We move all terms to the left:
1/(2x+6)-3/2x-(1/(x+3))=0
Domain of the equation: (2x+6)!=0
We move all terms containing x to the left, all other terms to the right
2x!=-6
x!=-6/2
x!=-3
x∈R
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: (x+3))!=0We calculate fractions
x∈R
(2x^2*()/((2x+6)*2x*(x+3)))+(-3*(2x+6)*(x+3)))/((2x+6)*2x*(x+3)))+(-(1*(2x+6)*2x)/((2x+6)*2x*(x+3)))=0
We calculate terms in parentheses: +(2x^2*()/((2x+6)*2x*(x+3))), so:
2x^2*()/((2x+6)*2x*(x+3))
We multiply all the terms by the denominator
2x^2*()
Back to the equation:
+(2x^2*())
We calculate terms in parentheses: +(-3*(2x+6)*(x+3)))/((2x+6)*2x*(x+3)))+(-(1*(2x+6)*2x)/((2x+6)*2x*(x+3))), so:
-3*(2x+6)*(x+3)))/((2x+6)*2x*(x+3)))+(-(1*(2x+6)*2x)/((2x+6)*2x*(x+3))
We add all the numbers together, and all the variables
-3*(2x+6)*(x+3)))/((2x+6)*2x*(x+3)))+(-(1*(2x+6)*2x)/((2x+6)*2x*(x
We multiply all the terms by the denominator
-3*(2x+6)*(x+3)))+6*2x*x*((2x+3))+(-(1*2x*((2x+6)*2x)+6*2x*x*((2x
Wy multiply elements
12x^3*x-3*(2x+6)*(x+3)))+6*2x*x*((2x+3))+(-(1*2x*((2x+6)*2x)
We do not support expression: x^3
See similar equations:
| 4x-30=909 | | 27=17+n | | 42r=-54 | | -8+12x=52 | | x+7+12/x=0 | | 3x13=10/5 | | -3(5x+8)=39-8x | | 5.9x+62=7.6+16 | | 50=60x | | 2/5×x+3-4/5×x=1/5 | | 0.4/x=0.2 | | 13t-5=0 | | 200=5s-(100-2s | | -44=-16+4n | | 9x-36=4x-6 | | -5x=2x+21 | | n=4n−3 | | 20=2v+16 | | 41-x=3x+7 | | 2x^2-3x-1=x^2+3x+6 | | (2x-30)+x+45=180 | | 3/7=t/4 | | 7*5a-4)-1=14-8a | | 14x-4=18x-6 | | 3x-12=9 | | -4=+3x | | 2x^2-3x-1=x^2=3x=6 | | 3+7+x=18 | | 42.76/m=93 | | 5t+3/4=3 | | (x+3)/3=(x+15)/3 | | 3/4 =k/11 |