1/(2x+7)=4/(7(x+2))

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Solution for 1/(2x+7)=4/(7(x+2)) equation: 


D( x )

2*x+7 = 0

7*(x+2) = 0

2*x+7 = 0

2*x+7 = 0

2*x+7 = 0 // - 7

2*x = -7 // : 2

x = -7/2

7*(x+2) = 0

7*(x+2) = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-7/2) U (-7/2:-2) U (-2:+oo)

1/(2*x+7) = 4/(7*(x+2)) // - 4/(7*(x+2))

1/(2*x+7)-(4/(7*(x+2))) = 0

1/(2*x+7)+(-4/7)*(x+2)^-1 = 0

1/(2*x+7)-4/7/(x+2) = 0

(1*(x+2))/((2*x+7)*(x+2))+(-4/7*(2*x+7))/((2*x+7)*(x+2)) = 0

1*(x+2)-4/7*(2*x+7) = 0

-1/7*x-2 = 0

(-1/7*x-2)/((2*x+7)*(x+2)) = 0

(-1/7*x-2)/((2*x+7)*(x+2)) = 0 // * (2*x+7)*(x+2)

-1/7*x-2 = 0

-1/7*x-2 = 0 // + 2

-1/7*x = 2 // : -1/7

x = 2/(-1/7)

x = -14

x = -14

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