1/(2x-4)=7/3

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Solution for 1/(2x-4)=7/3 equation: 


D( x )

2*x-4 = 0

2*x-4 = 0

2*x-4 = 0

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

x in (-oo:2) U (2:+oo)

1/(2*x-4) = 7/3 // - 7/3

1/(2*x-4)-(7/3) = 0

1/(2*x-4)-7/3 = 0

(1*3)/(3*(2*x-4))+(-7*(2*x-4))/(3*(2*x-4)) = 0

1*3-7*(2*x-4) = 0

31-14*x = 0

(31-14*x)/(3*(2*x-4)) = 0

(31-14*x)/(3*(2*x-4)) = 0 // * 3*(2*x-4)

31-14*x = 0

31-14*x = 0 // - 31

-14*x = -31 // : -14

x = -31/(-14)

x = 31/14

x = 31/14

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