1/(2x-5)+5/(2x-1)=2

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Solution for 1/(2x-5)+5/(2x-1)=2 equation: 



1/(2x-5)+5/(2x-1)=2

We move all terms to the left:

1/(2x-5)+5/(2x-1)-(2)=0



Domain of the equation: (2x-5)!=0

We move all terms containing x to the left, all other terms to the right

2x!=5

x!=5/2

x!=2+1/2

x∈R





Domain of the equation: (2x-1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=1

x!=1/2

x!=1/2

x∈R



We calculate fractions


(1*(2x-1))/((2x-5)*(2x-1))+(10x-25)/((2x-5)*(2x-1))-2=0



We calculate terms in parentheses: +(1*(2x-1))/((2x-5)*(2x-1)), so:

1*(2x-1))/((2x-5)*(2x-1)

We multiply all the terms by the denominator


1*(2x-1))

Back to the equation:

+(1*(2x-1)))





We calculate terms in parentheses: +(10x-25)/((2x-5)*(2x-1)), so:

10x-25)/((2x-5)*(2x-1)

We multiply all the terms by the denominator


10x*((2x-5)*(2x-1)-25)

Back to the equation:

+(10x*((2x-5)*(2x-1)-25))

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