1/(4+3)+1/(3x-2)=1

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Solution for 1/(4+3)+1/(3x-2)=1 equation: 


D( x )

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0 // + 2

3*x = 2 // : 3

x = 2/3

x in (-oo:2/3) U (2/3:+oo)

1/(3*x-2)+1/(3+4) = 1 // - 1

1/(3*x-2)+1/(3+4)-1 = 0

1/(3*x-2)+1/7-1 = 0

(1*7)/(7*(3*x-2))+(1*(3*x-2))/(7*(3*x-2))+(-1*7*(3*x-2))/(7*(3*x-2)) = 0

1*(3*x-2)-1*7*(3*x-2)+1*7 = 0

3*x-21*x+5+14 = 0

19-18*x = 0

(19-18*x)/(7*(3*x-2)) = 0

(19-18*x)/(7*(3*x-2)) = 0 // * 7*(3*x-2)

19-18*x = 0

19-18*x = 0 // - 19

-18*x = -19 // : -18

x = -19/(-18)

x = 19/18

x = 19/18

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