1/(4-x)+3/(6+x)=0

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Solution for 1/(4-x)+3/(6+x)=0 equation: 



1/(4-x)+3/(6+x)=0



Domain of the equation: (4-x)!=0

We move all terms containing x to the left, all other terms to the right

-x!=-4

x!=-4/-1

x!=+4

x∈R





Domain of the equation: (6+x)!=0

We move all terms containing x to the left, all other terms to the right

x!=-6

x∈R



We add all the numbers together, and all the variables

1/(-1x+4)+3/(x+6)=0

We calculate fractions


(1*(x+6))/((-1x+4)*(x+6))+(-3x+12)/((-1x+4)*(x+6))=0



We calculate terms in parentheses: +(1*(x+6))/((-1x+4)*(x+6)), so:

1*(x+6))/((-1x+4)*(x+6)

We multiply all the terms by the denominator


1*(x+6))

Back to the equation:

+(1*(x+6)))





We calculate terms in parentheses: +(-3x+12)/((-1x+4)*(x+6)), so:

-3x+12)/((-1x+4)*(x+6)

We multiply all the terms by the denominator


-3x*((-1x+4)*(x+6)+12)

Back to the equation:

+(-3x*((-1x+4)*(x+6)+12))

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