1/(4x)+25=50

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Solution for 1/(4x)+25=50 equation:


D( x )

4*x = 0

4*x = 0

4*x = 0

4*x = 0 // : 4

x = 0

x in (-oo:0) U (0:+oo)

1/(4*x)+25 = 50 // - 50

1/(4*x)-50+25 = 0

1/4*x^-1 = 25 // : 1/4

x^-1 = 100

-1 < 0

1/(x^1) = 100 // * x^1

1 = 100*x^1 // : 100

1/100 = x^1

x = 1/100

x = 1/100

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