1/(5-y)=1/8y

Solution for 1/(5-y)=1/8y equation:

1/(5-y)=1/8y

We move all terms to the left:

1/(5-y)-(1/8y)=0


Domain of the equation: (5-y)!=0

We move all terms containing y to the left, all other terms to the right

-y!=-5

y!=-5/-1

y!=+5

y∈R



Domain of the equation: 8y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

1/(-1y+5)-(+1/8y)=0

We get rid of parentheses

1/(-1y+5)-1/8y=0

We calculate fractions


8y/(-8y^2+40y)+(-1*(-1y+5))/(-8y^2+40y)=0


We calculate terms in parentheses: +(-1*(-1y+5))/(-8y^2+40y), so:

-1*(-1y+5))/(-8y^2+40y

determiningTheFunctionDomain
-8y^2-1*(-1y+5))/(+40y

We add all the numbers together, and all the variables

-8y^2+40y-1*(-1y+5))/(

We multiply all the terms by the denominator


-8y^2*(+40y*(-1*(-1y+5))

Back to the equation:

+(-8y^2*(+40y*(-1*(-1y+5)))


We multiply all the terms by the denominator


((-8y^2*(+40y*(-1*(-1y+5))))*(-8y^2+40y)+8y=0