1/(5x-1)-1/(x+2)=0

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Solution for 1/(5x-1)-1/(x+2)=0 equation: 



1/(5x-1)-1/(x+2)=0



Domain of the equation: (5x-1)!=0

We move all terms containing x to the left, all other terms to the right

5x!=1

x!=1/5

x!=1/5

x∈R





Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



We calculate fractions


(1*(x+2))/((5x-1)*(x+2))+(-1*(5x-1))/((5x-1)*(x+2))=0



We calculate terms in parentheses: +(1*(x+2))/((5x-1)*(x+2)), so:

1*(x+2))/((5x-1)*(x+2)

We multiply all the terms by the denominator


1*(x+2))

Back to the equation:

+(1*(x+2)))





We calculate terms in parentheses: +(-1*(5x-1))/((5x-1)*(x+2)), so:

-1*(5x-1))/((5x-1)*(x+2)

We multiply all the terms by the denominator


-1*(5x-1))

Back to the equation:

+(-1*(5x-1)))

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