1/(8x)-2/(3x)+5/(6x)=7/2

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Solution for 1/(8x)-2/(3x)+5/(6x)=7/2 equation: 



1/(8x)-2/(3x)+5/(6x)=7/2

We move all terms to the left:

1/(8x)-2/(3x)+5/(6x)-(7/2)=0



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R





Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



We add all the numbers together, and all the variables

1/8x-2/3x+5/6x-(+7/2)=0

We get rid of parentheses

1/8x-2/3x+5/6x-7/2=0

We calculate fractions

We do not support expression: x^3

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