1/(h+5)=1/(3(h+4))

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Solution for 1/(h+5)=1/(3(h+4)) equation:


D( h )

3*(h+4) = 0

h+5 = 0

3*(h+4) = 0

3*(h+4) = 0

h+4 = 0 // - 4

h = -4

h+5 = 0

h+5 = 0

h+5 = 0 // - 5

h = -5

h in (-oo:-5) U (-5:-4) U (-4:+oo)

1/(h+5) = 1/(3*(h+4)) // - 1/(3*(h+4))

1/(h+5)-(1/(3*(h+4))) = 0

1/(h+5)+(-1/3)*(h+4)^-1 = 0

1/(h+5)-1/3/(h+4) = 0

(1*(h+4))/((h+5)*(h+4))+(-1/3*(h+5))/((h+5)*(h+4)) = 0

1*(h+4)-1/3*(h+5) = 0

2/3*h+7/3 = 0

(2/3*h+7/3)/((h+5)*(h+4)) = 0

(2/3*h+7/3)/((h+5)*(h+4)) = 0 // * (h+5)*(h+4)

2/3*h+7/3 = 0

2/3*h+7/3 = 0 // - 7/3

2/3*h = -7/3 // : 2/3

h = -7/3/2/3

h = -7/2

h = -7/2

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