1/(n-8)-1=7/(n-8)

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Solution for 1/(n-8)-1=7/(n-8) equation:


D( n )

n-8 = 0

n-8 = 0

n-8 = 0

n-8 = 0 // + 8

n = 8

n in (-oo:8) U (8:+oo)

1/(n-8)-1 = 7/(n-8) // - 7/(n-8)

1/(n-8)-(7/(n-8))-1 = 0

1/(n-8)-7*(n-8)^-1-1 = 0

1/(n-8)-7/(n-8)-1 = 0

1/(n-8)-7/(n-8)+(-1*(n-8))/(n-8) = 0

1-1*(n-8)-7 = 0

8-n-6 = 0

2-n = 0

(2-n)/(n-8) = 0

(2-n)/(n-8) = 0 // * n-8

2-n = 0

2-n = 0 // - 2

-n = -2 // * -1

n = 2

n = 2

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