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1/(p-3)-3/(2p+6)=(15-p)/(2(p-3)(p+3))
We move all terms to the left:
1/(p-3)-3/(2p+6)-((15-p)/(2(p-3)(p+3)))=0
Domain of the equation: (p-3)!=0
We move all terms containing p to the left, all other terms to the right
p!=3
p∈R
Domain of the equation: (2p+6)!=0
We move all terms containing p to the left, all other terms to the right
2p!=-6
p!=-6/2
p!=-3
p∈R
Domain of the equation: (2(p-3)(p+3)))!=0We add all the numbers together, and all the variables
p∈R
1/(p-3)-3/(2p+6)-((-1p+15)/(2(p-3)(p+3)))=0
We use the square of the difference formula
p^2+1/(p-3)-3/(2p+6)+9=0
We calculate fractions
p^2+(1*(2p+6))/((p-3)*(2p+6))+(-3p+9)/((p-3)*(2p+6))+9=0
We calculate terms in parentheses: +(1*(2p+6))/((p-3)*(2p+6)), so:
1*(2p+6))/((p-3)*(2p+6)
We multiply all the terms by the denominator
1*(2p+6))
Back to the equation:
+(1*(2p+6)))
We calculate terms in parentheses: +(-3p+9)/((p-3)*(2p+6)), so:
-3p+9)/((p-3)*(2p+6)
We multiply all the terms by the denominator
-3p*((p-3)*(2p+6)+9)
Back to the equation:
+(-3p*((p-3)*(2p+6)+9))
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