1/(tan(2x))

Solution for 1/(tan(2x)) equation:

D( x )

tan(2*x) = 0

cos(2*x) = 0

tan(2*x) = 0

tan(2*x) = 0

tan(2*x) = 0  <=>  2*x = pi*k_1 i k_1 należy do I

t_1 = pi*k_1

2*x-t_1 = 0

2*x-t_1 = 0 // + t_1

2*x = t_1 // : 2

x = t_1/2

x = pi*k_1/2 i k_1 należy do I

cos(2*x) = 0

cos(2*x) = 0

cos(2*x) = 0  <=>  2*x = pi*k_2+pi/2 i k_2 należy do I

t_2 = pi*k_2+pi/2

2*x-t_2 = 0

2*x-t_2 = 0 // + t_2

2*x = t_2 // : 2

x = t_2/2

x = pi*k_2+pi/2/2 i k_2 należy do I

x in {( -oo : +oo ) / {< pi*k_1/2 : pi*k_1/2 > U < pi*k_2+pi/2/2 : pi*k_2+pi/2/2 >}} i k_2 -> {I}, k_1 -> {I}

1/tan(2*x) = 0

1/tan(2*x) = 0 // * tan(2*x)

1 = 0

x belongs to the empty set