1/(u-5)=1/(3u-1)

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Solution for 1/(u-5)=1/(3u-1) equation: 


D( u )

u-5 = 0

3*u-1 = 0

u-5 = 0

u-5 = 0

u-5 = 0 // + 5

u = 5

3*u-1 = 0

3*u-1 = 0

3*u-1 = 0 // + 1

3*u = 1 // : 3

u = 1/3

u in (-oo:1/3) U (1/3:5) U (5:+oo)

1/(u-5) = 1/(3*u-1) // - 1/(3*u-1)

1/(u-5)-(1/(3*u-1)) = 0

1/(u-5)-(3*u-1)^-1 = 0

1/(u-5)-1/(3*u-1) = 0

(1*(3*u-1))/((u-5)*(3*u-1))+(-1*(u-5))/((u-5)*(3*u-1)) = 0

1*(3*u-1)-1*(u-5) = 0

2*u+4 = 0

(2*u+4)/((u-5)*(3*u-1)) = 0

(2*u+4)/((u-5)*(3*u-1)) = 0 // * (u-5)*(3*u-1)

2*u+4 = 0

2*u+4 = 0 // - 4

2*u = -4 // : 2

u = -4/2

u = -2

u = -2

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