1/(v-2)=1/v-10/v

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Solution for 1/(v-2)=1/v-10/v equation: 


D( v )

v = 0

v-2 = 0

v = 0

v = 0

v-2 = 0

v-2 = 0

v-2 = 0 // + 2

v = 2

v in (-oo:0) U (0:2) U (2:+oo)

1/(v-2) = 1/v-(10/v) // - 1/v-(10/v)

1/(v-2)-(1/v)+10/v = 0

1/(v-2)-v^-1+10/v = 0

1/(v-2)-1/v+10/v = 0

(1*v)/(v*(v-2))+(-1*(v-2))/(v*(v-2))+(10*(v-2))/(v*(v-2)) = 0

10*(v-2)-1*(v-2)+1*v = 0

10*v-20+2 = 0

10*v-18 = 0

(10*v-18)/(v*(v-2)) = 0

(10*v-18)/(v*(v-2)) = 0 // * v*(v-2)

10*v-18 = 0

10*v-18 = 0 // + 18

10*v = 18 // : 10

v = 18/10

v = 9/5

v = 9/5

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