1/(w-1)-3/(4w-4)=1/(4w-4)

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Solution for 1/(w-1)-3/(4w-4)=1/(4w-4) equation:


D( w )

4*w-4 = 0

w-1 = 0

4*w-4 = 0

4*w-4 = 0

4*w-4 = 0 // + 4

4*w = 4 // : 4

w = 4/4

w = 1

w-1 = 0

w-1 = 0

w-1 = 0 // + 1

w = 1

w in (-oo:1) U (1:+oo)

1/(w-1)-(3/(4*w-4)) = 1/(4*w-4) // - 1/(4*w-4)

1/(w-1)-(3/(4*w-4))-(1/(4*w-4)) = 0

1/(w-1)-3*(4*w-4)^-1-(4*w-4)^-1 = 0

1/(w-1)-3/(4*w-4)-1/(4*w-4) = 0

(1*(4*w-4))/((w-1)*(4*w-4))+(-3*(w-1))/((w-1)*(4*w-4))+(-1*(w-1))/((w-1)*(4*w-4)) = 0

1*(4*w-4)-3*(w-1)-1*(w-1) = 0

w-w-1+1 = 0

0 = 0

0/((w-1)*(4*w-4)) = 0

0/((w-1)*(4*w-4)) = 0 // * (w-1)*(4*w-4)

0 = 0

w belongs to the empty set

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