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1/(x)+1/(2x+1)=7/10
We move all terms to the left:
1/(x)+1/(2x+1)-(7/10)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (2x+1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=-1
x!=-1/2
x!=-1/2
x∈R
1/x+1/(2x+1)-(+7/10)=0
We get rid of parentheses
1/x+1/(2x+1)-7/10=0
We calculate fractions
(-7x^2*()/(20x^2+10x)+(20x+10)/(20x^2+10x)+10x/(20x^2+10x)=0
We calculate terms in parentheses: +(-7x^2*()/(20x^2+10x)+(20x+10)/(20x^2+10x)+10x/(20x^2+10x), so:
-7x^2*()/(20x^2+10x)+(20x+10)/(20x^2+10x)+10x/(20x^2+10x
We calculate fractions
We do not support expression: x^3
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