1/(x)+1/(2x+1)=7/10

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Solution for 1/(x)+1/(2x+1)=7/10 equation: 



1/(x)+1/(2x+1)=7/10

We move all terms to the left:

1/(x)+1/(2x+1)-(7/10)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R



We add all the numbers together, and all the variables

1/x+1/(2x+1)-(+7/10)=0

We get rid of parentheses

1/x+1/(2x+1)-7/10=0

We calculate fractions


(-7x^2*()/(20x^2+10x)+(20x+10)/(20x^2+10x)+10x/(20x^2+10x)=0



We calculate terms in parentheses: +(-7x^2*()/(20x^2+10x)+(20x+10)/(20x^2+10x)+10x/(20x^2+10x), so:

-7x^2*()/(20x^2+10x)+(20x+10)/(20x^2+10x)+10x/(20x^2+10x

We calculate fractions

We do not support expression: x^3

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