1/(x+1)+3=7/(x+1)

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Solution for 1/(x+1)+3=7/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

1/(x+1)+3 = 7/(x+1) // - 7/(x+1)

1/(x+1)-(7/(x+1))+3 = 0

1/(x+1)-7*(x+1)^-1+3 = 0

1/(x+1)-7/(x+1)+3 = 0

1/(x+1)-7/(x+1)+(3*(x+1))/(x+1) = 0

3*(x+1)-7+1 = 0

3*x-6+3 = 0

3*x-3 = 0

(3*x-3)/(x+1) = 0

(3*x-3)/(x+1) = 0 // * x+1

3*x-3 = 0

3*x-3 = 0 // + 3

3*x = 3 // : 3

x = 3/3

x = 1

x = 1

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