1/(x+1)+x/(4x+4)=1

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Solution for 1/(x+1)+x/(4x+4)=1 equation: 



1/(x+1)+x/(4x+4)=1

We move all terms to the left:

1/(x+1)+x/(4x+4)-(1)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (4x+4)!=0

We move all terms containing x to the left, all other terms to the right

4x!=-4

x!=-4/4

x!=-1

x∈R



We calculate fractions


(1*(4x+4))/((x+1)*(4x+4))+(x^2+x)/((x+1)*(4x+4))-1=0



We calculate terms in parentheses: +(1*(4x+4))/((x+1)*(4x+4)), so:

1*(4x+4))/((x+1)*(4x+4)

We multiply all the terms by the denominator


1*(4x+4))

Back to the equation:

+(1*(4x+4)))





We calculate terms in parentheses: +(x^2+x)/((x+1)*(4x+4)), so:

x^2+x)/((x+1)*(4x+4)

We multiply all the terms by the denominator


x^2*((x+1)*(4x+4)+x)

Back to the equation:

+(x^2*((x+1)*(4x+4)+x))

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