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1/(x+2)+2=9/(x+2)
We move all terms to the left:
1/(x+2)+2-(9/(x+2))=0
Domain of the equation: (x+2)!=0
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
Domain of the equation: (x+2))!=0We calculate fractions
x∈R
(1*(x+2)))/((x+2)*(x+2)))+(-(9*(x+2))/((x+2)*(x+2)))+2=0
We can not solve this equation
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