1/(x+2)-1/(x+1)

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Solution for 1/(x+2)-1/(x+1) equation:


D( x )

x+2 = 0

x+1 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-2) U (-2:-1) U (-1:+oo)

1/(x+2)-(1/(x+1)) = 0

1/(x+2)-(x+1)^-1 = 0

1/(x+2)-1/(x+1) = 0

(1*(x+1))/((x+2)*(x+1))+(-1*(x+2))/((x+2)*(x+1)) = 0

1*(x+1)-1*(x+2) = 0

-1 = 0

-1/((x+2)*(x+1)) = 0

-1/((x+2)*(x+1)) = 0 // * (x+2)*(x+1)

-1 = 0

x belongs to the empty set

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