1/(x+3)+1/(x-3)=1/(x-3)(x+3)

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Solution for 1/(x+3)+1/(x-3)=1/(x-3)(x+3) equation: 


D( x )

x-3 = 0

x+3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

1/(x+3)+1/(x-3) = (1/(x-3))*(x+3) // - (1/(x-3))*(x+3)

1/(x+3)+1/(x-3)-((1/(x-3))*(x+3)) = 0

1/(x+3)+1/(x-3)-((x-3)^-1*(x+3)) = 0

1/(x+3)+1/(x-3)+(-1*(x+3))/(x-3) = 0

(1*(x-3))/((x+3)*(x-3))+(1*(x+3))/((x+3)*(x-3))+(-1*(x+3)^2)/((x+3)*(x-3)) = 0

1*(x-3)+1*(x+3)-1*(x+3)^2 = 0

2*x-x^2-6*x-9 = 0

-x^2-4*x-9 = 0

-x^2-4*x-9 = 0

-1*(x^2+4*x+9) = 0

x^2+4*x+9 = 0

DELTA = 4^2-(1*4*9)

DELTA = -20

DELTA < 0

-1 = 0

-1/((x+3)*(x-3)) = 0

-1/((x+3)*(x-3)) = 0 // * (x+3)*(x-3)

-1 = 0

x belongs to the empty set

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