1/(x+3)+1/x=1/2

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Solution for 1/(x+3)+1/x=1/2 equation: 



1/(x+3)+1/x=1/2

We move all terms to the left:

1/(x+3)+1/x-(1/2)=0



Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: x!=0

x∈R



We add all the numbers together, and all the variables

1/(x+3)+1/x-(+1/2)=0

We get rid of parentheses

1/(x+3)+1/x-1/2=0

We calculate fractions


(-1x^2-3x)/((x+3)*x*2)+4x/((x+3)*x*2)+(2x+6)/((x+3)*x*2)=0



We calculate terms in parentheses: +(-1x^2-3x)/((x+3)*x*2), so:

-1x^2-3x)/((x+3)*x*2

We multiply all the terms by the denominator


-1x^2*((x+3)*x*2-3x)

Back to the equation:

+(-1x^2*((x+3)*x*2-3x))





We calculate terms in parentheses: +(2x+6)/((x+3)*x*2), so:

2x+6)/((x+3)*x*2

We multiply all the terms by the denominator


2x*((x+3)*x*2+6)

Back to the equation:

+(2x*((x+3)*x*2+6))



We multiply all the terms by the denominator


((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2)+4x+((2x*((x+3)*x*2+6)))*((x+3)*x*2)=0



We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





We calculate terms in parentheses: +((2x*((x+3)*x*2+6)))*((x+3)*x*2), so:

(2x*((x+3)*x*2+6)))*((x+3)*x*2





We calculate terms in parentheses: +((-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2), so:

(-1x^2*((x+3)*x*2-3x)))*((x+3)*x*2





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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