1/(x-3)+4/(5x-15)

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Solution for 1/(x-3)+4/(5x-15) equation: 


D( x )

5*x-15 = 0

x-3 = 0

5*x-15 = 0

5*x-15 = 0

5*x-15 = 0 // + 15

5*x = 15 // : 5

x = 15/5

x = 3

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

1/(x-3)+4/(5*x-15) = 0

(1*(5*x-15))/((x-3)*(5*x-15))+(4*(x-3))/((x-3)*(5*x-15)) = 0

1*(5*x-15)+4*(x-3) = 0

9*x-27 = 0

(9*x-27)/((x-3)*(5*x-15)) = 0

(9*x-27)/((x-3)*(5*x-15)) = 0 // * (x-3)*(5*x-15)

9*x-27 = 0

9*x-27 = 0 // + 27

9*x = 27 // : 9

x = 27/9

x = 3

x in { 3} 

x belongs to the empty set

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